JEE Main & Advanced Chemistry Nuclear chemistry Question Bank Critical Thinking Nuclear chemistry

  • question_answer The half-life of \[_{6}{{C}^{14}}\], if its decay constant is \[6.31\times {{10}^{-4}}\] is  [CBSE PMT 2001]

    A)            1098 yrs                                  

    B)            109.8 yrs

    C)            10.98 yrs                                

    D)            1.098 yrs

    Correct Answer: A

    Solution :

           \[{{t}_{1/2}}=\frac{0.693}{k}=\frac{0.693}{6.31\times {{10}^{-4}}}\]\[=0.1098\times {{10}^{4}}=1098yrs\].

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