A) \[{{C}_{2}}{{H}_{5}}Cl+Mg\xrightarrow{\text{dryethe}r}\]
B) \[{{C}_{2}}{{H}_{5}}Cl+LiAl{{H}_{4}}\xrightarrow{{}}\]
C) \[{{C}_{2}}{{H}_{5}}Cl+{{C}_{2}}{{H}_{5}}ONa\xrightarrow{{}}\]
D) \[CHC{{l}_{3}}\underset{\Delta }{\mathop{\xrightarrow{Ag\ \text{powder}}}}\,\]
Correct Answer: B
Solution :
Wurtz reaction gives ethane \[2C{{H}_{3}}I+2Na\underset{\text{ether}}{\mathop{\xrightarrow{\text{dry}}}}\,{{C}_{2}}{{H}_{6}}+2NaI\] Similarly \[{{C}_{2}}{{H}_{5}}Cl\] reduced by \[LiAl{{H}_{4}}\] to give ethane \[{{C}_{2}}{{H}_{5}}Cl+2H\xrightarrow{LiAl{{H}_{4}}}{{C}_{2}}{{H}_{6}}+HCl\]
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