JEE Main & Advanced Chemistry Carboxylic Acids Question Bank Critical Thinking Carboxylic Acids

  • question_answer
    \[R-C{{H}_{2}}-C{{H}_{2}}OH\] can be converted into \[RC{{H}_{2}}C{{H}_{2}}COOH.\] The correct sequence of the reagents is [AIIMS 1997]

    A)                 \[PB{{r}_{3}},KCN,{{H}_{3}}{{O}^{+}}\]  

    B)                 \[PB{{r}_{3}},KCN,{{H}_{2}}\]

    C)                 \[HCN,PB{{r}_{3}},{{H}^{+}}\]    

    D)                 \[KCN,{{H}^{+}}\]

    Correct Answer: A

    Solution :

               \[R-C{{H}_{2}}C{{H}_{2}}OH\xrightarrow{PB{{r}_{3}}}R-C{{H}_{2}}C{{H}_{2}}-Br\]\[\xrightarrow{KCN}R-C{{H}_{2}}-C{{H}_{2}}-CN\xrightarrow{{{H}_{3}}{{O}^{+}}}\]                                                                     \[R-C{{H}_{2}}-C{{H}_{2}}COOH+N{{H}_{3}}\]


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