A) \[\pi \]
B) \[-\pi \]
C) \[-\frac{\pi }{2}\]
D) \[\frac{\pi }{2}\]
Correct Answer: A
Solution :
Since arg \[z<0\] i.e. - ve, we choose arg z = - q where \[\theta \] is \[{{\left( \frac{1-z}{1-\frac{1}{z}} \right)}^{10}}\] arg \[(-z)=-[+\pi -(-\theta )]\] \[=-\pi -\theta =2\pi +(-\pi -\theta )=\pi +arg(z)\] \[\Rightarrow \,arg\,(-z)-arg(z)=\pi .\]
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