A) \[\frac{\pi }{2}\]
B) \[-\frac{\pi }{2}\]
C) 0
D) \[\frac{\pi }{4}\]
Correct Answer: C
Solution :
\[arg\left( \frac{3+i}{2-i}+\frac{3-i}{2+i} \right)=arg\left( \frac{6+5i+{{i}^{2}}+6-5i+{{i}^{2}}}{5} \right)\] \[=arg\left( \frac{10}{5} \right)=0\].
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