A) \[|z|\,=\,|\bar{z}|\]
B) \[z.\,\bar{z}=|\bar{z}{{|}^{2}}\]
C) \[\overline{{{z}_{1}}+{{z}_{2}}}=\overline{{{z}_{1}}}+\overline{{{z}_{2}}}\]
D) \[arg\,z=arg\,\bar{z}\]
Correct Answer: D
Solution :
Let \[z=x+iy,\overline{z}=x-iy\] Since \[arg(z)=\theta ={{\tan }^{-1}}\frac{y}{x}\] \[arg(\overline{z})=\theta ={{\tan }^{-1}}\left( \frac{-y}{x} \right)\] Thus \[arg(z)\ne arg(\overline{z})\].
You need to login to perform this action.
You will be redirected in
3 sec
