A) \[\operatorname{Re}(z)>0\]
B) \[\operatorname{Re}(z)<0\]
C) \[\operatorname{Re}(z)>2\]
D) None of these
Correct Answer: D
Solution :
Given inequality \[|z-4|\,<\,|z-2|\] \[\Rightarrow \] \[|z-4{{|}^{2}}<\,|z-2{{|}^{2}}\Rightarrow {{(x-4)}^{2}}+{{y}^{2}}<{{(x-2)}^{2}}+{{y}^{2}}\] Þ \[4x>12\Rightarrow \operatorname{Re}(z)>3\].
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