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7th Class Mathematics Congruence of Triangles Question Bank Congruence of Triangles

  • question_answer
    DIRECTION: Study the figure and information given below carefully and answer the following questions.
                             
    CF and AE are equal perpendiculars on BD, BF = FE = ED.
    \[\Delta \,ABE\] is congruent to

    A)  \[\Delta \,AED\]      

    B)  \[\Delta \,BFC\]          

    C)         \[\Delta \,CDF\]       

    D)         \[\Delta \,BCD\]

    Correct Answer: C

    Solution :

    In AABE and \[\Delta \,CDF\] AE = CF (given) \[\angle AEB=\angle CFD={{90}^{o}}\] (given) \[BF+FE=DE+EF\] \[\Rightarrow \] BE = DF \[\Rightarrow \]\[\Delta ABE\cong \Delta CDF\] (By SAS)


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