A) \[\frac{1}{3}\]
B) \[\frac{1}{2}\]
C) \[\frac{1}{12}\]
D) None of these
Correct Answer: B
Solution :
Since 4 has appeared on the first, so we are required 4 or 5 or 6 on second dice. Hence required probability \[=\frac{3}{6}=\frac{1}{2}.\]You need to login to perform this action.
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