A) \[1-P\,\left( \frac{A}{B} \right)\]
B) \[1-P\,\left( \frac{{\bar{A}}}{B} \right)\]
C) \[\frac{1-P\,(A\cup B)}{P\,(\bar{B})}\]
D) \[\frac{P\,(\bar{A})}{P\,(\bar{B})}\]
Correct Answer: C
Solution :
\[P\left( \frac{\overline{A}}{\overline{B}} \right)=\frac{P(\overline{A}\cap \overline{B})}{P(\bar{B})}=\frac{P(\overline{A\cup B})}{P(\bar{B})}=\frac{1-P(A\cup B)}{P(\bar{B})}.\]You need to login to perform this action.
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