A) 3/4
B) 5
C) -15
D) -20
Correct Answer: A
Solution :
\[{{x}^{2}}-3x+3={{\left( x-\frac{3}{2} \right)}^{2}}+\frac{3}{4}\] Therefore, smallest value is \[\frac{3}{4}\], which lie in \[\left( -3,\frac{3}{2} \right)\]
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