A) A. P.
B) G. P.
C) H. P.
D) None of these
Correct Answer: A
Solution :
It is given that the lines\[ax+2y+1=0\], \[bx+3y+1=0\] and \[cx+4y+1=0\] are concurrent, therefore \[\left| \,\begin{matrix} a & 2 & 1 \\ b & 3 & 1 \\ c & 4 & 1 \\ \end{matrix}\, \right|=0\] Þ \[-a+2b-c=0\Rightarrow 2b=a+c\] Þ \[a,b,c\]are in A. P.You need to login to perform this action.
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