A) Cold water
B) Dilute \[{{H}_{2}}S{{O}_{4}}\]
C) Dilute \[HCl\]
D) Hot 20% \[NaOH\]
Correct Answer: A
Solution :
Zn does not react with cold water. However it reacts with hot water and yield \[{{H}_{2}}\] \[Zn+{{H}_{2}}O\xrightarrow{\text{Boil}}ZnO+{{H}_{2}}\] \[Zn+{{H}_{2}}S{{O}_{4}}(\text{dil})\to ZnS{{O}_{4}}+{{H}_{2}}\] \[Zn+2HCl\,(\text{dil})\to ZnC{{l}_{2}}+{{H}_{2}}\] \[Zn+\underset{20%}{\mathop{2NaOH}}\,\xrightarrow{\text{heat}}N{{a}_{2}}Zn{{O}_{2}}+{{H}_{2}}\]
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