A) \[NaN{{O}_{3}}\]
B) \[N{{a}_{2}}C{{O}_{3}}\]
C) \[N{{a}_{2}}{{S}_{2}}{{O}_{3}}\]
D) \[N{{H}_{4}}OH\]
Correct Answer: A
Solution :
\[NaN{{O}_{3}}\] is purely ionic while AgCl is covalent other compounds reacts with \[AgCl\] \[2AgCl+N{{a}_{2}}C{{O}_{3}}\to 2Ag+2NaCl+C{{O}_{2}}+\frac{1}{2}{{O}_{2}}\] \[AgCl+2N{{a}_{2}}C{{O}_{3}}\to N{{a}_{2}}[Ag{{({{S}_{2}}{{O}_{3}})}_{2}}]+NaCl\] \[AgCl+2N{{H}_{4}}OH\to [Ag{{(N{{H}_{3}})}_{2}}Cl]+2{{H}_{2}}O\]
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