A) \[s{{p}^{3}}\]
B) \[{{d}^{2}}s{{p}^{3}}\]
C) \[s{{p}^{3}}d\]
D) \[s{{p}^{2}}\]
Correct Answer: A
Solution :
In the compound \[[Ni{{(CO)}_{4}}]\] Oxidation number of \[Ni=0\] Co-ordination number of \[Ni=4\] (Co (carbonyl) is a strong ligand so it cause pairing of electron)
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