A) \[ScC{{l}_{3}}\]
B) \[Ti{{O}_{2}}\]
C) \[MnS{{O}_{4}}\]
D) \[ZnS{{O}_{4}}\]
Correct Answer: C
Solution :
\[MnS{{O}_{4}}\,\to \,M{{n}^{2+}}+SO_{4}^{2-}\]
due to presence of unpaired electrons it will form coloured salt.
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