A) \[Cr{{O}_{2}}C{{l}_{2}}\]
B) \[CrO_{4}^{2-}\]
C) \[C{{r}^{3+}}\]
D) \[C{{r}^{2+}}\]
Correct Answer: C
Solution :
\[C{{r}_{2}}O_{7}^{2-}+8{{H}^{+}}+2SO_{3}^{2-}\,\to \,2C{{r}^{+3}}+3SO_{4}^{2-}+4{{H}_{2}}O\]
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