A) 294
B) 298
C) 49
D) 50
Correct Answer: C
Solution :
\[{{K}_{2}}C{{r}_{2}}{{O}_{7}}+3{{H}_{2}}S{{O}_{4}}\,\to {{K}_{2}}S{{O}_{4}}+C{{r}_{2}}{{(S{{O}_{4}})}_{3}}+3\,(O)+3{{H}_{2}}\] No. of electrons lossed = 12 - 6 = 6 \ Equivalent weight = \[\frac{M}{6}=\frac{294}{6}=49.\]
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