8th Class Mathematics Comparing Quantities Question Bank Comparing Queantities

  • question_answer A landlord has a large piece of agricultural land which he wants to sell. James wants to buy the land and buys it for Rs. 400000. After some time he was in need of money and wanted to sell that land piece. He sell one third of the land at the loss of 20% and two fifth at the gain of 25%. At what price he must sell the remaining land so that he can make the overall profit of 10% on the whole transaction?

    A)  Rs.\[\frac{800000}{3}\]            

    B)  Rs.\[\frac{400000}{3}\] 

    C)  Rs. \[\frac{320000}{3}\]           

    D)  Rs.\[\frac{920000}{3}\]

    Correct Answer: B

    Solution :

    (b): C.P = 400000 \[\frac{1}{3}\]rd of it \[\Rightarrow \frac{400000}{3}\] sold at 20% loss             \[=\frac{400000}{3}\times \left( 1-\frac{20}{100} \right)\] \[=\frac{400000\times 0.8}{3}/-\] \[\frac{2}{5}\]th of it \[\Rightarrow \frac{400000\times 2}{5}\]sold out of 25% gain \[=\frac{400000\times 2}{5}\times \left( 1+\frac{25}{100} \right)\] \[=400000\times 0.4\times 1.25\] \[=200000/-\] Remaining land =\[\left( 1-\frac{1}{3}-\frac{2}{5} \right)\]             \[=\left( \frac{15-5-6}{15} \right)\] \[=\frac{4}{15}\] part. C.P OF \[=\frac{4}{15}\]part = \[400000\times \frac{4}{15}\] Let S.P \[=\frac{4}{15}\]part be 'x' Overall \[S.P=400000\times \left( 1+\frac{10}{100} \right)=440000\] \[\therefore 400000\times \frac{0.8}{3}+200000+x=440000\] \[\Rightarrow x=400000-\frac{320000}{3}\] \[\Rightarrow x=\frac{400000}{3}\]Rs/-


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