• # question_answer A exceeds b by$12\frac{1}{2}%$. By what percentage is a more than b?     A) $6\frac{1}{4}%$                      B)  $12\frac{1}{2}%$C) $25%$             D) $20%$

(b) This is a TRIVIAL (Common sense) question. The statement of the problem itself signifies that a is $=\frac{100}{900}\times 100%=\frac{1}{9}\times 100%=11\frac{1}{9}%$ more than b.