A) Impurities dissolves in \[HCl\]
B) The value of \[[N{{a}^{+}}]\]and \[[C{{l}^{-}}]\] becomes smaller than \[{{K}_{sp}}\] of \[NaCl\]
C) The value of \[[N{{a}^{+}}]\]and \[[C{{l}^{-}}]\] becomes greater than \[{{K}_{sp}}\] of \[NaCl\]
D) \[HCl\]dissolves in the water
Correct Answer: C
Solution :
\[NaC{{l}_{(s)}}\] ⇌ \[N{{a}^{+}}_{(\text{aq})}+C{{l}^{-}}_{(\text{aq})}\] \[HCl\] ⇌ \[{{H}^{+}}+C{{l}^{-}}\] The increase in \[[C{{l}^{-}}]\] brings in an increase in \[[N{{a}^{+}}]\,\,\]\[[C{{l}^{-}}]\]which will lead for backward reaction because \[{{K}_{sp}}\,NaCl=[N{{a}^{+}}]\,\,[C{{l}^{-}}]\].
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