A) \[1.69\times {{10}^{-9}}mol\,litr{{e}^{-1}}\]
B) \[1.69\times {{10}^{-18}}mol\,litr{{e}^{-1}}\]
C) \[3.6\times {{10}^{-18}}mol\,litr{{e}^{-1}}\]
D) \[3.6\times {{10}^{-5}}mol\,litr{{e}^{-1}}\]
Correct Answer: D
Solution :
\[BaS{{O}_{4}}\]⇌\[\underset{(S)\,\,\,\,}{\mathop{B{{a}^{++}}}}\,+\underset{(S)\,\,\,\,}{\mathop{SO_{4}^{-\,-}}}\,\] \[{{K}_{sp}}={{S}^{2}};\,\,S=\sqrt{{{K}_{sp}}}=\sqrt{1.3\times {{10}^{-9}}}\] \[=3.6\times {{10}^{-5}}\,\,\,mol/litre\]
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