JEE Main & Advanced Chemistry Equilibrium Question Bank Common ion effect, Isohydric solutions, Solubility product, Ionic product of water and salt hydrolysis

  • question_answer The solubility product of \[BaS{{O}_{4}}\] is \[1.3\times {{10}^{-9}}\]. The solubility of this salt in pure water will be          [MP PET 2002]

    A)                 \[1.69\times {{10}^{-9}}mol\,litr{{e}^{-1}}\]        

    B)                 \[1.69\times {{10}^{-18}}mol\,litr{{e}^{-1}}\]

    C)                 \[3.6\times {{10}^{-18}}mol\,litr{{e}^{-1}}\]        

    D)                 \[3.6\times {{10}^{-5}}mol\,litr{{e}^{-1}}\]

    Correct Answer: D

    Solution :

    \[BaS{{O}_{4}}\]⇌\[\underset{(S)\,\,\,\,}{\mathop{B{{a}^{++}}}}\,+\underset{(S)\,\,\,\,}{\mathop{SO_{4}^{-\,-}}}\,\]                    \[{{K}_{sp}}={{S}^{2}};\,\,S=\sqrt{{{K}_{sp}}}=\sqrt{1.3\times {{10}^{-9}}}\]                                 \[=3.6\times {{10}^{-5}}\,\,\,mol/litre\]

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