A) \[1\times {{10}^{-3}}gm\,\,mol\,/\,litre\]
B) \[1\times {{10}^{-5}}gm\,\,mol\,/\,litre\]
C) \[1\times {{10}^{-4}}gm\,\,mol\,/\,litre\]
D) \[1\times {{10}^{-2}}gm\,\,mol\,/\,litre\]
Correct Answer: C
Solution :
\[A{{B}_{2}}\]⇌\[\underset{(S)\,}{\mathop{{{A}^{2+}}}}\,+\underset{{{(2S)}^{2}}}{\mathop{2{{B}^{-}}}}\,\] \[{{K}_{sp}}=4{{S}^{3}}\] \[S=\sqrt[3]{\frac{{{K}_{sp}}}{4}}=\sqrt[3]{\frac{4\times {{10}^{-12}}}{4}}\] \[=1\times {{10}^{-4}}\,\,gm.\,mol/litre\]
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