JEE Main & Advanced Chemistry Equilibrium Question Bank Common ion effect, Isohydric solutions, Solubility product, Ionic product of water and salt hydrolysis

  • question_answer The saturated solution of \[A{{g}_{2}}S{{O}_{4}}\] is \[2.5\times {{10}^{-2}}\,M.\] Its solubility product \[({{K}_{sp}})\] is                  [NCERT 1980]

    A)                 \[62.5\times {{10}^{-6}}\]            

    B)                 \[6.25\times {{10}^{-4}}\]

    C)                 \[15.625\times {{10}^{-6}}\]       

    D)                 \[3.125\times {{10}^{-6}}\]

    Correct Answer: A

    Solution :

                    \[{{K}_{sp}}=4{{s}^{3}}=4\times {{[2.5\times {{10}^{-2}}]}^{3}}=62.5\times {{10}^{-6}}\].

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