JEE Main & Advanced Chemistry Equilibrium Question Bank Common ion effect, Isohydric solutions, Solubility product, Ionic product of water and salt hydrolysis

  • question_answer The solubility of \[PbC{{l}_{2}}\] at \[{{25}^{o}}C\] is \[6.3\times {{10}^{-3}}\]mole/litre. Its solubility product at that temperature is [NCERT 1979; CPMT 1985]

    A)                 \[(6.3\times {{10}^{-3}})\times (6.3\times {{10}^{-3}})\]

    B)                 \[(6.3\times {{10}^{-3}})\times (12.6\times {{10}^{-3}})\]

    C)                 \[(6.3\times {{10}^{-3}})\times {{(12.6\times {{10}^{-3}})}^{2}}\]

    D)                 \[(12.6\times {{10}^{-3}})\times (12.6\times {{10}^{-3}})\]

    Correct Answer: C

    Solution :

               \[PbC{{l}_{2}}\to \underset{S}{\mathop{P{{b}^{++}}}}\,+\underset{2S}{\mathop{2C{{l}^{-}}}}\,\]                 \[{{K}_{sp}}=S\times {{(2S)}^{2}}\]\[=[6.3\times {{10}^{-3}}]\times {{[12.6\times {{10}^{-3}}]}^{2}}\].


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