JEE Main & Advanced Chemistry Equilibrium Question Bank Common ion effect, Isohydric solutions, Solubility product, Ionic product of water and salt hydrolysis

  • question_answer If the solubility product of \[BaS{{O}_{4}}\]is \[1.5\times {{10}^{-9}}\]in water, its solubility in moles per litre, is [BHU 1995; MP PET 1995; UPSEAT 204]

    A)                 \[1.5\times {{10}^{-9}}\]              

    B)                 \[3.9\times {{10}^{-5}}\]

    C)                 \[7.5\times {{10}^{-5}}\]              

    D)                 \[1.5\times {{10}^{-5}}\]

    Correct Answer: B

    Solution :

               \[BaS{{O}_{4}}\]⇌\[B{{a}^{2+}}+SO_{4}^{-\,-}\]                    Solubility constant \[=S\times S\]                                 \[1.5\times {{10}^{-19}}={{S}^{2}}\];\[S=\sqrt{1.5\times {{10}^{-19}}}\];\[S=3.9\times {{10}^{-5}}\]


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