A) \[1.5\times {{10}^{-9}}\]
B) \[3.9\times {{10}^{-5}}\]
C) \[7.5\times {{10}^{-5}}\]
D) \[1.5\times {{10}^{-5}}\]
Correct Answer: B
Solution :
\[BaS{{O}_{4}}\]⇌\[B{{a}^{2+}}+SO_{4}^{-\,-}\] Solubility constant \[=S\times S\] \[1.5\times {{10}^{-19}}={{S}^{2}}\];\[S=\sqrt{1.5\times {{10}^{-19}}}\];\[S=3.9\times {{10}^{-5}}\]
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