JEE Main & Advanced Chemistry Equilibrium Question Bank Common ion effect, Isohydric solutions, Solubility product, Ionic product of water and salt hydrolysis

  • question_answer The solubility product of \[AgCl\] is \[4.0\times {{10}^{-10}}\] at \[298\,\,K.\] The solubility of \[AgCl\]in \[0.04\,m\,\,CaC{{l}_{2}}\] will be [KCET 1996]

    A)                 \[2.0\times {{10}^{-5}}\,m\]       

    B)                 \[1.0\times {{10}^{-4}}\,m\]

    C)                 \[5.0\times {{10}^{-9}}\,m\]       

    D)                 \[2.2\times {{10}^{-4}}\,m\]

    Correct Answer: C

    Solution :


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