A) \[2\times {{10}^{-4}}\,m/s\]
B) \[16\times {{10}^{-4}}\,m/s\]
C) \[8\times {{10}^{-4}}\,m/s\]
D) \[8\times {{10}^{-8}}\,m/s\]
Correct Answer: A
Solution :
\[\underset{S}{\mathop{AgCr{{O}_{4}}}}\,\to \underset{2S}{\mathop{2A{{g}^{+}}}}\,+\underset{S}{\mathop{Cr{{O}_{4}}^{-\,\,-}}}\,\] \[{{K}_{sp}}={{(2S)}^{2}}S=4{{S}^{3}}\] \[S={{\left( \frac{{{K}_{sp}}}{4} \right)}^{\frac{1}{3}}}\]\[={{\left( \frac{32\times {{10}^{-12}}}{4} \right)}^{\frac{1}{3}}}\] \[=2\times {{10}^{-4}}\]M.
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