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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Common ion effect, Isohydric solutions, Solubility product, Ionic product of water and salt hydrolysis

  • question_answer
    The solubility product of \[1\times {{10}^{-5}}\] is \[1.44\times {{10}^{-4}}\] at\[{{100}^{o}}C\]. The solubility of silver chloride in boiling water may be [MP PMT 1994; Bihar MEE 1998]

    A)                 \[0.72\times {{10}^{-4}}\,M\]    

    B)                 \[1.20\times {{10}^{-2}}\,M\]

    C)                 \[{{80}^{o}}C,\]

    D)                 \[0.5\,M\,HCOOH,\]

    Correct Answer: B

    Solution :

               AgCl  ⇌ \[[A{{g}^{+}}]\,\,[C{{l}^{-}}]\] ;\[{{K}_{sp}}=S\times S\] ; \[{{K}_{sp}}={{S}^{2}}\]                                 \[S=\sqrt{{{K}_{sp}}}\]\[=\sqrt{1.44\times {{10}^{-4}}}\] \[=1.20\times {{10}^{-2}}\]M.    


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