JEE Main & Advanced Chemistry Equilibrium Question Bank Common ion effect, Isohydric solutions, Solubility product, Ionic product of water and salt hydrolysis

  • question_answer The solubility of \[PbC{{l}_{2}}\]is             [MP PMT 1995; DCE 1999]

    A)                 \[\sqrt{{{K}_{sp}}}\]      

    B)                 \[^{3}\sqrt{{{K}_{sp}}}\]

    C)                 \[^{3}\sqrt{\frac{{{K}_{sp}}}{4}}\]           

    D)                 \[\sqrt{8{{K}_{sp}}}\]

    Correct Answer: C

    Solution :

               \[PbC{{l}_{2}}\]  ⇌\[\underset{S\,\,}{\mathop{P{{b}^{2+}}}}\,+\underset{S\,\,}{\mathop{2C{{l}^{-}}}}\,\]                    \[{{K}_{sp}}\]of \[PbC{{l}_{2}}=[P{{b}^{2+}}]\times {{[C{{l}^{-}}]}^{2}}\] ;\[{{K}_{sp}}=S\times {{(2S)}^{2}}\]                                 \[{{K}_{sp}}=S\times 4{{S}^{2}}\]\[=4{{S}^{3}}\]; \[{{S}^{3}}=\frac{{{K}_{sp}}}{4}\]; \[S=\sqrt[3]{\frac{{{K}_{sp}}}{4}}\]


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