A) \[0.2\,\,M\]
B) \[1.2\times {{10}^{-10}}\,M\]
C) \[0.2\times {{10}^{-10}}\,M\]
D) \[0.2\times {{10}^{-10}}\,M\]
Correct Answer: D
Solution :
\[\underset{a}{\mathop{AgCl}}\,\]⇌\[\underset{a}{\mathop{A{{g}^{+}}}}\,+\underset{a}{\mathop{C{{l}^{-}}}}\,\] \[\underset{0.02}{\mathop{NaCl}}\,\]⇌ \[\underset{0.02\,\,\,\,\,}{\mathop{N{{a}^{+}}}}\,\,\,+\underset{0.02\,\,\,\,\,\,}{\mathop{C{{l}^{-}}}}\,\] \[{{K}_{sp}}\,\,AgCl=1.20\times {{10}^{-10}}\] \[{{K}_{sp}}\,\,AgCl=[A{{g}^{+}}]\,\,[C{{l}^{-}}]\]\[=a\times [a+0.2]\] \[={{a}^{2}}+0.2a\] \[{{a}^{2}}\]is a very small so it is a neglected. \[{{K}_{sp}}\,\,AgCl=0.2a\] \[1.20\times {{10}^{-10}}=0.2a\] \[a=\frac{1.20\times {{10}^{-10}}}{0.20}=6\times {{10}^{-10}}\]mole
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