A) \[1\times {{10}^{-5}}\]
B) \[1\times {{10}^{-10}}\]
C) \[1\times {{10}^{-15}}\]
D) \[1\times {{10}^{-20}}\]
Correct Answer: B
Solution :
The solubility of \[BaS{{O}_{4}}\]in g/litre is given \[2.33\times {{10}^{-3}}\] \[\because \]in mole/litre.\[n=\frac{W}{m.\,wt}\]\[=1\times {{10}^{-5}}\]\[=\,\frac{2.33\times {{10}^{-3}}}{233}\] Because \[BaS{{O}_{4}}\]is a compound \[{{K}_{sp}}={{S}^{2}}={{[1\times {{10}^{-5}}]}^{2}}\] \[=1\times {{10}^{-10}}\]
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