JEE Main & Advanced Chemistry Equilibrium Question Bank Common ion effect, Isohydric solutions, Solubility product, Ionic product of water and salt hydrolysis

  • question_answer The solubility of \[BaS{{O}_{4}}\] in water is \[2.33\times {{10}^{-3}}\,gm/litre.\] Its solubility product will be (molecular weight of \[BaS{{O}_{4}}=233)\]               [AIIMS 1998]

    A)                 \[1\times {{10}^{-5}}\]  

    B)                 \[1\times {{10}^{-10}}\]

    C)                 \[1\times {{10}^{-15}}\]               

    D)                 \[1\times {{10}^{-20}}\]

    Correct Answer: B

    Solution :

               The solubility of \[BaS{{O}_{4}}\]in g/litre is given \[2.33\times {{10}^{-3}}\]                    \[\because \]in mole/litre.\[n=\frac{W}{m.\,wt}\]\[=1\times {{10}^{-5}}\]\[=\,\frac{2.33\times {{10}^{-3}}}{233}\]                    Because \[BaS{{O}_{4}}\]is a compound                                 \[{{K}_{sp}}={{S}^{2}}={{[1\times {{10}^{-5}}]}^{2}}\] \[=1\times {{10}^{-10}}\]

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