JEE Main & Advanced Chemistry Equilibrium Question Bank Common ion effect, Isohydric solutions, Solubility product, Ionic product of water and salt hydrolysis

  • question_answer
    At 298 K, the solubility product of \[PbC{{l}_{2}}\] is \[1.0\times {{10}^{-6}}\]. What will be the solubility of \[PbC{{l}_{2}}\]in moles/litre [MP PMT 1990; CPMT 1985, 96]

    A)                 \[6.3\times {{10}^{-3}}\]              

    B)                 \[1.0\times {{10}^{-3}}\]

    C)                 \[3.0\times {{10}^{-3}}\]              

    D)                 \[4.6\times {{10}^{-14}}\]

    Correct Answer: A

    Solution :

               \[{{K}_{sp}}=4{{s}^{3}}\]                                  \[S=\sqrt[3]{\frac{{{K}_{sp}}}{4}}=\sqrt[3]{\frac{1.0\times {{10}^{-6}}}{4}}\]\[=6.3\times {{10}^{-3}}\].


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