A) \[0.001\,M\,AgN{{O}_{3}}\]
B) Pure water
C) \[0.30\,\,M\]
D) \[0.01\,M\,NaCl\]
Correct Answer: C
Solution :
0.01 M \[CaC{{l}_{2}}\]gives maximum \[C{{l}^{-}}\]ions to keep \[{{K}_{sp}}\]of AgCl constant, decrease in \[[A{{g}^{+}}]\]will be maximum.
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