JEE Main & Advanced Chemistry Equilibrium Question Bank Common ion effect, Isohydric solutions, Solubility product, Ionic product of water and salt hydrolysis

  • question_answer Solubility product of \[BaC{{l}_{2}}\] is \[4\times {{10}^{-9}}\]. Its solubility in moles/litre would be [AFMC 1982; Roorkee 1990; BHU 2000]

    A)                 \[1\times {{10}^{-3}}\]  

    B)                 \[1\times {{10}^{-9}}\]

    C)                 \[4\times {{10}^{-27}}\]               

    D)                 \[1\times {{10}^{-27}}\]

    Correct Answer: A

    Solution :

               \[{{K}_{sp}}=4{{S}^{3}},\]  \[{{S}^{3}}=\frac{4\times {{10}^{-9}}}{4}={{10}^{-9}}\]                                 \[\therefore \,S={{10}^{-3}}M\].

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