A) \[NaHC{{O}_{3}}\]
B) \[Ca(OCl)Cl\]
C) \[{{K}_{2}}S{{O}_{4}}\,A{{l}_{2}}{{(S{{O}_{4}})}_{3}}.24{{H}_{2}}O\]
D) \[Mg\,(OH)Br\]
Correct Answer: B
Solution :
\[CaOC{{l}_{2}}\] has two anions \[C{{l}^{-}}\]and \[OC{{l}^{-}}\]along with \[C{{a}^{2+}}\]ions.
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