A) \[108\times {{10}^{-25}}\]
B) \[1.0\times {{10}^{-25}}\]
C) \[144\times {{10}^{-25}}\]
D) \[126\times {{10}^{-24}}\]
Correct Answer: A
Solution :
\[S{{b}_{2}}{{S}_{3}}\ \to \ \underset{2x\,}{\mathop{2S{{b}^{+2}}}}\,+\underset{3x\,\,\,\,}{\mathop{3{{S}^{--}}}}\,\]; \[{{K}_{sp}}={{(2x)}^{2}}.{{(3x)}^{3}}\] \[{{K}_{sp}}=108{{x}^{5}}\] ; \[{{K}_{sp}}=108\times {{(1\times {{10}^{-5}})}^{5}}\] \[=108\times {{10}^{-25}}\].
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