JEE Main & Advanced Chemistry Equilibrium Question Bank Common ion effect, Isohydric solutions, Solubility product, Ionic product of water and salt hydrolysis

  • question_answer The solubility of \[S{{b}_{2}}{{S}_{3}}\]in water is \[1.0\times {{10}^{-5}}\]mol / litre at 298 K. What will be its solubility product                [CPMT 2004]

    A)                 \[108\times {{10}^{-25}}\]           

    B)                 \[1.0\times {{10}^{-25}}\]

    C)                 \[144\times {{10}^{-25}}\]           

    D)                 \[126\times {{10}^{-24}}\]

    Correct Answer: A

    Solution :

               \[S{{b}_{2}}{{S}_{3}}\ \to \ \underset{2x\,}{\mathop{2S{{b}^{+2}}}}\,+\underset{3x\,\,\,\,}{\mathop{3{{S}^{--}}}}\,\]; \[{{K}_{sp}}={{(2x)}^{2}}.{{(3x)}^{3}}\]                                 \[{{K}_{sp}}=108{{x}^{5}}\] ; \[{{K}_{sp}}=108\times {{(1\times {{10}^{-5}})}^{5}}\] \[=108\times {{10}^{-25}}\].


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