JEE Main & Advanced Chemistry Equilibrium Question Bank Common ion effect, Isohydric solutions, Solubility product, Ionic product of water and salt hydrolysis

  • question_answer The solubility product of a sparingly soluble salt \[A{{X}_{2}}\]is \[3.2\times {{10}^{-11}}\]. Its solubility (in moles / litres) is  [CBSE PMT 2004]

    A)                 \[2\times {{10}^{-4}}\]  

    B)                 \[4\times {{10}^{-4}}\]

    C)                 \[5.6\times {{10}^{-6}}\]              

    D)                 \[3.1\times {{10}^{-4}}\]

    Correct Answer: A

    Solution :

               \[A{{X}_{2}}\to \underset{x}{\mathop{A}}\,\ \ +\ \ \underset{2x}{\mathop{2X}}\,\]                                 \[{{K}_{sp}}=4{{x}^{3}}\] ; \[x=\sqrt[3]{\frac{3.2\times {{10}^{-11}}}{4}}\]; \[x=2\times {{10}^{-4}}\]mole/litre.   


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