A) \[62.5\times {{10}^{-6}}\]
B) \[6.25\times {{10}^{-4}}\]
C) \[15.625\times {{10}^{-6}}\]
D) \[3.125\times {{10}^{-6}}\]
Correct Answer: A
Solution :
For \[A{{g}_{2}}S{{O}_{4}}\to \underset{2x}{\mathop{2A{{g}^{+}}}}\,+\underset{x}{\mathop{SO_{4}^{--}}}\,\] \[{{K}_{sp}}={{(2x)}^{2}}.x\] ; \[{{K}_{sp}}=4{{x}^{3}}\] ; \[{{K}_{sp}}=4\times {{(2.5\times {{10}^{-2}})}^{3}}\] \[{{K}_{sp}}=62.5\times {{10}^{-6}}\]
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