A) Rs. 8800
B) Rs. 8890
C) Rs. 8920
D) Rs. 9040
Correct Answer: C
Solution :
Let the sum be Rs. x. Then .....(i) \[x{{\left( 1+\frac{R}{100} \right)}^{3}}=13380\] and \[x{{\left( 1+\frac{R}{100} \right)}^{6}}=20070\] ?..(II) Dividing equation (ii) by (0, we get \[{{\left( 1+\frac{R}{100} \right)}^{3}}=\left( \frac{20070}{13380} \right)=\left( \frac{3}{2} \right)\] \[\therefore \] \[x\frac{3}{2}=13380\] \[\Rightarrow \] \[x=\left( 13380\times \frac{2}{3} \right)=8920\] Hence, the sum is \[Rs.\text{ }8920\]
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