A) \[H-O-\overset{\,O\,}{\mathop{\underset{H}{\mathop{\underset{|\,}{\mathop{\underset{\,O\,}{\mathop{\underset{|\,}{\overset{\uparrow \,}{\mathop{P}}}\,}}\,}}\,}}\,}}\,-O-H\]
B) \[O\leftarrow \underset{\,H\,}{\mathop{\underset{|\,}{\mathop{\underset{\,O\,}{\overset{\,H\,}{\mathop{\underset{|\,}{\overset{|}{\mathop{P}}}\,}}}\,}}\,}}\,-O-H\]
C) \[O\leftarrow \underset{H\,}{\overset{H}{\mathop{\underset{|\,\,\,}{\overset{|\,\,}{\mathop{P\,}}}\,}}}\,-O-H\]\[\]
D) \[H-O-\overset{\,O}{\mathop{\overset{\uparrow }{\mathop{P}}\,}}\,=O\]\[\]
Correct Answer: A
Solution :
\[{{H}_{3}}P{{O}_{4}}\]is orthophosphoric acid. \[H-O-\underset{\underset{\underset{H}{\mathop{|}}\,}{\mathop{O}}\,}{\overset{O}{\mathop{\underset{|}{\overset{\uparrow }{\mathop{P}}}\,}}}\,-O-H\]
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