A) 7
B) 9
C) 12
D) 15
Correct Answer: D
Solution :
The grid consists of each square as unit square. Hence, each side is of a unit length, i.e. 1. Now, the given polygon has two sides parallel. Hence, this forms? a trapezium. Now, Area of the trapezium \[=\frac{1}{2}\times ({{b}_{1}}+{{b}_{2}})\times h\] where, \[{{b}_{1}}\] and are the lengths of the two parallel sides. As the side on the top of the trapezium covers 3 unit squares, the length of this side is 3 units. i.e. \[{{b}_{1}}=3\] units. Similarly, the side on the bottom covers 7 unit squares, the length of this side is 7 units. i.e., \[{{b}_{2}}=7\] units Again the two parallel sides are away from each other by 3 squares. i.e., \[h=3\] \[\therefore \] Area of trapezium \[=\frac{1}{2}\times (7+3)\times 3\] \[=\frac{1}{2}\times 10\times 3=15\]
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