A) \[5\,\pi \]
B) \[15\,\pi \]
C) \[25\,\pi \]
D) \[50\,\pi \]
Correct Answer: D
Solution :
Here, we are asked to find the area of the circle. First we have to find the radius of the given circle. Choose a point \[(5,5)\] and drop a perpendicular from this point on the x-axis. This gives a right triangle with the radius of the circle as the hypotenuse. The length of base of the triangle is the distance from the origin to the perpendicular and equal to the x- co-ordinate of point \[(5,5)\]. Other leg will also be equal to 3, the y- co-ordinate of point \[(5,5)\] Now, both the leg's of the right triangle are 5. Hence it is an isosceles triangle. Hypotenuse of right triangle = Radius of circle. \[=\sqrt{2}\] (Leg of the right triangle) \[=5\sqrt{2}\] Area of given circle \[\pi \](radius)2 \[=\pi (5\sqrt{2})2=50\pi \]
You need to login to perform this action.
You will be redirected in
3 sec
