A) 5-aminohex-2-ene carboxylic acid
B) 5-amino-2-heptenoic acid
C) 3-amino-5-heptenoic acid
D) \[\beta -\] amino-\[\delta -\]heptenoic acid
Correct Answer: C
Solution :
\[\underset{3-\text{amino-5-heptenoic acid}}{\mathop{\overset{7\,\,\,\,\,\,\,\,}{\mathop{C{{H}_{3}}}}\,-\overset{6\,\,}{\mathop{CH}}\,=\overset{5\,\,\,\,}{\mathop{CH}}\,-\overset{4\,\,\,\,\,\,}{\mathop{C{{H}_{2}}}}\,-\underset{N{{H}_{2}}}{\mathop{\underset{|\,\,\,\,\,}{\overset{3\,\,\,}{\mathop{CH}}}\,}}\,-\overset{2\,\,\,\,\,\,}{\mathop{C{{H}_{2}}}}\,-\overset{1\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{COOH}}\,}}\,\]
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