A) \[{{60}^{o}}\]
B) \[{{58}^{o}}\]
C) \[{{62}^{o}}\]
D) None of these
Correct Answer: A
Solution :
Given, \[\angle DAB={{62}^{o}},\angle ABD={{180}^{o}}\] In \[\Delta \Alpha DB,\angle DAB+\angle ABD+\angle ADB={{180}^{o}}\] \[\Rightarrow \]\[{{62}^{o}}+{{58}^{o}}+\angle ADB={{180}^{o}}\] \[\Rightarrow \]\[\angle ADB={{180}^{o}}-{{120}^{o}}={{60}^{o}}\] Now, \[\angle ACB=\angle ADB={{60}^{o}}\] (Angles in same segment are equal)
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