A) \[{{40}^{o}}\]
B) \[{{50}^{o}}\]
C) \[{{60}^{o}}\]
D) \[{{65}^{o}}\]
Correct Answer: B
Solution :
\[\angle ABC={{90}^{o}}\] [Angle in a semicircle ] In \[\Delta ABC,\] we have \[\angle ABC+\angle CAB+\angle ABC={{180}^{o}}\] \[\Rightarrow \] \[{{50}^{o}}+\angle CAB+{{90}^{o}}={{180}^{o}}\] \[\Rightarrow \] \[\angle CAB={{40}^{o}}\] Now, \[\angle CAT={{90}^{o}}\Rightarrow \angle CAB+\angle BAT={{90}^{o}}\] \[\Rightarrow \] \[{{40}^{o}}+\angle BAT={{90}^{o}}\Rightarrow \angle BAT={{50}^{o}}\]You need to login to perform this action.
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