A) \[{{110}^{o}}\]
B) \[{{100}^{o}}\]
C) \[{{90}^{o}}\]
D) \[{{120}^{o}}\]
Correct Answer: A
Solution :
Given \[\angle BEC={{130}^{o}}\]and \[\angle ECD={{20}^{o}}\] Now, \[\angle ABD=\angle ACD\] (Angles in same segment) \[\therefore \]\[\angle ABD={{20}^{o}}\] Now, in \[\Delta \Alpha \Epsilon \Beta \] \[\angle EBA+\angle BAE=\angle BEC\] \[\Rightarrow \]\[{{20}^{o}}+\angle BAC={{130}^{o}}\] \[\Rightarrow \]\[\angle BAC={{110}^{o}}\]
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